ConCat using variables generated by Separate

vanfanel · Post by **vanfanel** » Sat Sep 11, 2004 1:39 pm

Why doesn't this combination of Separate and ConCat work?

Let>files=a;b;c;d
Separate>files,;,file_names
Let>file_names_count=4

Let>k=0
Repeat>k
Let>k=k+1
ConCat>file_names_%k%,1
Message>file_names_%k%
Wait>1
Until>k,file_names_count

Lumumba · Post by **Lumumba** » Sat Sep 11, 2004 3:46 pm

ConCat>string1,string2

Concatenates string1 with string2. String1 must be a variable containing a string. String2 can be a literal string or a variable. The result is that string1 has string2 appended to it.

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I guess what you expect here won't work, as its a mixed up var/literal
ConCat>file_names_%k%,1

Bob Hansen · Post by **Bob Hansen** » Sat Sep 11, 2004 5:58 pm

I am also confused by

Let>file_names_count=4

You do not need the Let> line. That is one of the features of using Separate>, you don't need to know how many items are being separated, in fact it tells you.

You appear to be assigning a value here to a variable (file_names_count) that is assigned by the previous Separate command. Is it just coincidence that you used 4?

After running Separate> insert a Message>

Let>files=a;b;c;d
Separate>files,;,file_names
Message>Number of files is %file_names_count%

and you will see that 4 is the value in your sample.