Midstr alternative method (or enhancement)

[tbrahmer]

Looking for a good way to return the remaining characters from a string just given a starting point...
For instance, to return 'End', I know I can use:

Code: Select all

Let>string=BeginEnd
MidStr>string,6,3,result1
Let>result2={copy(%string%,6,3)}

But using these methods require me to provide a length for the substrings, so I have always had to compute the total length, subtract where my starting point is, etc...

Was hoping for solution similar to many programming languages where if you omit the length, it will just return all the remaining characters till it hits the end of the string. Something like this...

Code: Select all

Let>string=BeginEnd
MidStr>string,6,,result1
Let>result2={copy(%string%,6)}

Is there a simple solution that I am missing, or should I call this an enhancement request... Thoughts?

[Jerry Thomas]

Try just putting some number > than the string could ever be
I use 100 most of the time

[Marcus Tettmar]

You could also do:

Code: Select all

Let>string=BeginEnd
Let>result={copy(%string%,6,length(%string%))}

So you're still finding length but it's all done in-line.

[tbrahmer]

Thanks Jerry and Marcus, will use your suggestions.