String Replace Cmd

CyberCitizen · Post by **CyberCitizen** » Fri Nov 11, 2005 4:30 am

String Replace Cmd.

StringReplace>sourcestring,find,replace,newstring

What I Am Trying To Do Is Replace The ,'s In A Set Of Numbers.

Eg The Numbers Are Listed 58,452,197

What I Want To Be Able To Do Is Replace The ,'s With Nothing.

The Stand Way Does Not Work As It Treats The Commas As A Seperator.

StringReplace>sourcestring,find,replace,newstring
StringReplace>58,452,197,,,,NewNumber

Bob Hansen · Post by **Bob Hansen** » Fri Nov 11, 2005 4:57 am

Try the following (untested)
--------------------------------------

Let>Source=58,452,197
Let>Find=,
StringReplace>%Source%,%Find%,,NewNumber
MessageModal>New Number is %NewNumber%

Me_again · Post by **Me_again** » Fri Nov 11, 2005 5:24 am

Shamelessly stealing the idea from a post by support I can reveal that it's very easy with vbscript

VBSTART
VBEND
..
Let>oldnum=111,222,333
VBEval>Replace("%oldnum%",",",""),newnum
MessageModal>newnum

support · Post by **support** » Fri Nov 11, 2005 8:04 am

As Bob suggests, if you ever need to pass a comma as a parameter just make a variable for it first:

Let>comma=,
StringReplace>string,comma,replace,newstring

This works whichever command you need to use.